Answer:
[tex]x = \frac{ - 7± \sqrt{37} }{2} [/tex]
Step-by-step explanation:
[tex] {x}^{2} + 7x + 3 = 0[/tex]
[tex] \frac{ - b± \sqrt{ {b}^{2} - 4(ac) } }{2a} [/tex]
[tex] \frac{ - 7± \sqrt{ {7}^{2} - 4(1 \times 3)} }{2 \times 1} [/tex]
[tex]x = \frac{ - 7± \sqrt{37} }{2 \times 1} [/tex]
[tex]x = \frac{ - 7± \sqrt{37} }{2} [/tex]
Hope it is helpful....
