Answer:
7.01 hope this is right !
Explanation:
This problem can be summarized thusly:
qlost by copper = qgained by water + qgained by calorimeter
2) Therefore:
(610. g) (95.3 °C − x) (0.387 J g¯1 K¯1) = (45.0 g) (x − 36.5 °C) (4.184 J g¯1 °C¯1) + [(10.0 J/K) (x − 36.5 °C)]
Comment: The K and the °C cancel because the °C in this problem is a temperature difference (not one single specific value) and the "size" of one K = one °C.
22497.471 − 236.07x = 198.28x − 7237.22
424.35x = 29734.691
x = 70.1 °C
