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  • 22-11-2016
  • Mathematics
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Differentiate: y=1+cosx/1-cosx ...?

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 23-11-2016
The answer for the given question above would be calculated as:

 y = (1 + cos(x)) / (1 - cos(x)) 

Using the quotient rule. 

dy/dx = [ (-sin(x)) (1 - cos(x)) - (1 + cos(x)) (sin(x)) ] / [ (1 - cos(x))^2 ] 

dy/dx = [ -sin(x) + sin(x)cos(x) - sin(x) - sin(x)cos(x) ] / [ 1 - cos(x) ]^2 

dy/dx = [ -2sin(x) ] / [ 1 - cos(x) ]^2 

The answer is dy/dx = [ -2sin(x) ] / [ 1 - cos(x) ]^2 
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