a0lexibertSehanna a0lexibertSehanna
  • 21-11-2016
  • Mathematics
contestada

Give the excluded value(s) for the following fraction.

y+5/y^2+4y-32

Respuesta :

antonsandiego
antonsandiego antonsandiego
  • 22-11-2016
Since we can divide by 0, we can clearly see that  there  is no way denominator can be 0. So, lets start :[tex]y^2+4y-32=0[/tex].
The exluded  values are lying in the y and we hav eto find them :[tex]y^2+4y-32=(y+8)*(y-4)=0[/tex]
According to the info above,[tex]y+8=0 or y-4=0[/tex]
y is -8 and 4. 
That's all!
Answer Link
ethanpetersonxe
ethanpetersonxe ethanpetersonxe
  • 02-01-2020

Answer:

y is -8 and 4.

Step-by-step explanation:

Answer Link

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