Jankin3o6kaunieh Jankin3o6kaunieh
  • 21-11-2016
  • Mathematics
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tan(arcsin(x)) and its domain ...?

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alsteva alsteva
  • 24-11-2016
[tex]- \frac{\pi}{2} < \arcsin{x} < \frac{\pi}{2} \\ \\\sin(- \frac{\pi}{2}) < \sin(\arcsin{x}) < \sin(\frac{\pi}{2} ) \\ \\-1 < x < 1[/tex]
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