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Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 16 m/s at an angle 47 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.

What is the maximum height the ball goes above the ground?

Respuesta :

v^2 = u^2 + 2as

0 = (16 sin 47)^2 + 2 (-9.81)s

s = 6.98m

= 7.0m (2s . f)

Hence, maximum height is 8.5 m

hope this helps

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