Respuesta :

[tex] \frac{7i}{8+i} \\ \\ \frac{7i}{8+i} \times \frac{8-i}{8-i} \\ \\ \frac{7i(8-i)}{(8+i)(8-i)} \\ \\ \frac{56i-7i^2}{64-i^2} \\ \\ \frac{56i-7(-1)}{64-(-1)} \\ \\ \frac{56i+7}{64+1} \\ \\ \frac{56i+7}{65} \\ \\ \frac{56}{65}i + \frac{7}{65} [/tex]

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