jacquelinedawn6699 jacquelinedawn6699
  • 26-03-2021
  • Chemistry
contestada

¿Cuántos gramos de dicloruro de manganeso se obtienen cuando reaccionan 7,5 g de ácido clorhídrico? MnO2 + 4 HCl = Mn Cl2 + Cl2 + 2 H2O *

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pstnonsonjoku
pstnonsonjoku pstnonsonjoku
  • 27-03-2021

Answer:

6.6 g

Explanation:

La ecuación de la reacción es;

MnO2 + 4 HCl -------> MnCl2 + Cl2 + 2H2O

Número de moles de HCl que reaccionan = 7.5g / 36.5 g / mol = 0.21 moles

Dado que;

4 moles de HCl producen 1 mol de MnCl2

0,21 moles de HCl producen 0,21 * 1/4 = 0,0525 moles de MnCl2.

Masa de MnCl2 = 125,844 g / mol * 0,0525 moles = 6.6 g

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