teixeirasage5434 teixeirasage5434
  • 25-03-2021
  • Mathematics
contestada

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 25-03-2021

Answer:

BC = 205.8 feet

Step-by-step explanation:

Please see attached photo

From the attached photo:

Angle B = 71°

Adjacent = BD = 67 feet

Hypothenus = BC = x

The value of x can be obtained as follow:

Cos B = Adjacent / Hypothenus

Cos 71 = 67 / x

0.3256 = 67 / x

Cross multiply

0.3256 × x = 67

Divide both side by 0.3256

x = 67 / 0.3256

x = 205.8 feet

Therefore BC = 205.8 feet

Ver imagen Eduard22sly
Answer Link

Otras preguntas

What City in France was originally a Greek City state?
The volume of a pyramid with a square base is given by the expression 1/3s^2h, where s is the length of a side of the base and h is the height. Find the volume
How are the energy needs of plant cells similar to those of animal cells how are they different
Help please!!!!!!!!!!!!!!!!!!!!!!
In which part of the body is glycogen stored?
X and y intercepts of the equation 2x-3y=7 ?
7 out of 10 students got full marks on their test. Calculate the angle you would use in a pie chart
a block of mass M is initially at rest on a frictional less floor. the block, attached to a massless spring with spring constant k, is initially at its equilibr
A car travels west for 240km in 4hr. What is the cars velocity?
the tens digit of a two digit number is twice the units digit. The sum of the digits is twelve. Find the original number.