Answer:
See proof below
Step-by-step explanation:
Given that m = (3x-1) and n = (3x+1)
Taking the product
mn = (3x-1)(3x+1)
mn = 9x^2+3x-3x-1
mn = 9x^2 - 1
mn+1 = (9x^2-1+1)
mn+1 = 9x^2
Dividing both sides by 9
(mn+1)/9 = (9x^2)/9
(mn+1)/9 = x^2
Swap
x^2 = (mn+1)/9
This shows the required proof
