Answer:
when x = 3 1/3, y = 4.5
or
when x =3 , y = 5
Step-by-step explanation:
Here, we want to solve using substitution
xy = 15
let x = 15/y
Put this into the first equation;
3(15/y) + 2y = 19
45/y + 2y = 19
Multiply through by y
45 + 2y^2 = 19y
2y^2 -19y + 45 = 0
2y^2 - 10y - 9y + 45 = 0
2y(y-5) -9(y-5) = 0
(2y-9)(y-5) = 0
2y-9 = 0
or y-5 = 0
2y = 9 or y = 5
y = 9/2 or y = 5
y = 4.5 or y = 5
Recall;
x = 15/y
x = 15/4.5 or x = 15/5
x = 3 1/3 or x = 3
