A force of 200N was required to pull the arrow back 0.25m in the bow. If the archer were to release the bowstring how much energy would the arrow gain?

Respuesta :

Answer:

50 Joules

Explanation:

Work (J) = Force (N) x Distance (m)

Work (J) = 200 N x 0.25 m

Work = 50 Joules

Work is converted to kinetic energy when the arrow is released.