Answer:
3√-6×√2 Imaginary numbers
[tex]3 \sqrt{ - 6} \times \sqrt{2} \\ = 3 \sqrt{ - 1 \times 3\times2 \times 2} \\ = 3 \times 2 \times \sqrt{ - 1} \times \sqrt{3} \\ = \boxed{ 6 \sqrt{3} i}[/tex]
