Answer:
(2x-3)(2x+3)
Step-by-step explanation:
Not sure what you mean by solve for x but here's how you factor!
You can write both the 4 and -9 in exponential form:
[tex]2^2x^2-3^2[/tex]
Multiply the terms that have equal exponents by multiplying their bases:
[tex](2x)^2-3^2[/tex]
Use the form [tex]a^2-b^2=(a-b)(a+b)[/tex] to factor:
(2x-3)(2x+3)
Hope this helps! :)
