deidretitus12 deidretitus12

25-01-2021
Mathematics

contestada

How many liters of pure alchol must be added to 20l of a 40% solution to obtain a 60% solution ?

Respuesta :

rococo908 rococo908

25-01-2021

Answer:

10 liters of pure alcohol

Step-by-step explanation:

Create an equation where x is the number of liters of pure alcohol needed:

1x + (0.4)(20) = (20 + x)(0.6)

Simplify:

x + 8 = 0.6x + 12

Solve for x:

0.4x = 4

x = 10

So, 10 liters of pure alcohol have to be added

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