Answer:
V = 5.6 L
Explanation:
Given data:
Number of moles of C₄H₁₀ = 0.25 mol
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Volume of C₄H₁₀ = ?
Solution:
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 0.25 mol × 0.0821 atm.L /mol.K × 273.15 K
V = 5.6 atm.L/ 1 atm
V = 5.6 L
