D=[tex] \sqrt{(x1-x2)^2+(y1-y2)^2} [/tex] given distance between (-6,5) and (-3,y) is 5 5=[tex] \sqrt{(-6-(-3))^2+(5-y)^2} [/tex] 5=[tex] \sqrt{(-6+3)^2+(5-y)^2} [/tex] 5=[tex] \sqrt{(-3)^2+(5-y)^2} [/tex] 5=[tex] \sqrt{9+y^2-10t+25} [/tex] 5=[tex] \sqrt{y^2-10t+34} [/tex] square both sides 25= [tex] y^2-10t+34 [/tex] minus 25 both sides [tex] 0= y^2-10t+9 [/tex] factor 0=(y-9)(y-1) set to zero 0=y-9 9=y
