ginazarza
ginazarza ginazarza
  • 23-10-2016
  • Chemistry
contestada

as a step O3 0.020 mol to gr

Respuesta :

Willchemistry
Willchemistry Willchemistry
  • 23-10-2016
Molar mass:

Atomic mass O = 16.0 a.m.u

O₃ = 16.0 x 3 => 48.0 g/mol

Therefore:

1 mole O₃ --------------- 48.0 g
0.020 mole O₃ ---------- ??

0.020 x 48.0 / 1 =

0.96 / 1 => 0.96 g 

hope this helps!
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