Answer:
Explanation:
Given parameters:
Mass of water = 40g
Initial temperature = 33°C
Final temperature = 23°C
Specific heat capacity of water = 4.2J/g°C
Unknown:
Quantity of heat = ?
Solution:
To solve this problem, we use the expression below;
H = m c Δt
H is the quantity of heat
m is the mass
c is the specific heat capacity
Δt is the change in temperature
H = 40 x 4.2 x (23 - 33) = -1680J
The water will have to lose 1680J of heat to bring it to that final temperature.
