Given:
[tex]x^2-6xy+36y^2[/tex]
To find:
Whether the given trinomial is a perfect trinomial or not.
Solution:
We have,
[tex]x^2-6xy+36y[/tex]
It can be written as
[tex]=x^2-6xy+6^2y^2[/tex]
[tex]=x^2-(x)(6y)+(6y)^2[/tex]
This equation is not of the form [tex](a-b)^2=a^2-2ab+b^2[/tex] because in the above expression, 2 is missing in the middle term.
Therefore, the given trinomial is not a perfect square.
