Answer:
See below
Step-by-step explanation:
Given points:
- A (3, -1)
, B (9, 2)
, C (6, -4)
First, plot the points on the coordinate plane (see attached)
We see that AB and BC look the same. Let's find their length:
- AB = [tex]\sqrt{(9-3)^2+(2-(-1))^2} = \sqrt{6^2+3^2} = \sqrt{45} = 3\sqrt{5}[/tex]
- BC = [tex]\sqrt{(6-9)^2 + (-4-2)^2} = \sqrt{3^2 + (-6)^2} = \sqrt{45} = 3\sqrt{5}[/tex]
We showed that AB = BC = 3√5, so the triangle has two sided of the same length, therefore is isosceles.
