jrmontiel11
jrmontiel11 jrmontiel11
  • 25-11-2020
  • Mathematics
contestada

Find tan-1 1.4281 to the nearest degree.
a. 10°
b. 55°
C. 5°
d. 35°

Respuesta :

absor201
absor201 absor201
  • 25-11-2020

Answer:

[tex]\:x=55^{\circ \:\:}[/tex]

Therefore, option 'b' is correct.

Step-by-step explanation:

Let x be the angle

  • tan x = 1.4281

determining the [tex]\tan ^{-1}\left(1.4281\:\right)[/tex]

[tex]\:\tan \:x\:=1.4281\:[/tex]

[tex]x=\tan ^{-1}\left(1.4281\:\right)[/tex]

[tex]\:x=55^{\circ \:\:}[/tex]

Therefore, option 'b' is correct.

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