Answer:
no
Step-by-step explanation:
1. to make up the equations of lines PQ and RS:
(PQ) [tex]\frac{x-0}{2} =\frac{y+9}{1}; \ \frac{x}{2}=\frac{y+9}{1};[/tex]
(RS) [tex]\frac{x-1}{-2}=\frac{y-4}{1}; \ \frac{x-1}{-2}=\frac{y-4}{1};[/tex]
2. to write the pointed verctors of PQ and RS:
for PQ it is p=(2;1); for RS it is r=(-2;1).
3. according to the pointed vectors it is clear, the given lines are not perpendicular [2*(-2)+1*1≠0].
