Answer:
[tex] \sqrt {32} [/tex]
Step-by-step explanation:
Next term of the given AP can be obtained by adding common difference (d) in the last term [tex] \sqrt {18}[/tex]
[tex]d = \sqrt{18} - \sqrt{8} = 3 \sqrt{2} - 2 \sqrt{2} = \sqrt{2} \\ next \: term = \sqrt{18} + \sqrt{2} \\ = 3 \sqrt{2} + \sqrt{2} \\ = 4 \sqrt{2} \\ = \sqrt{ {4}^{2} \times 2 } \\ = \sqrt{16 \times 2} \\ \huge \red{ \boxed{next \: term = \sqrt{32} }}[/tex]
