sarahjmatthews7361 sarahjmatthews7361
  • 23-07-2020
  • Physics
contestada

Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6 N. ¿Cuál es el nuevo alargamiento?

Respuesta :

whitneytr12
whitneytr12 whitneytr12
  • 24-07-2020

Answer:

[tex]k=784 N/m[/tex]

[tex]\Delta x=8,8 cm[/tex]

Explanation:

Usando la ley de Hook tenemos:

[tex]F=k\Delta x[/tex]

Solving it for k we have:

[tex]k=\frac{F}{\Delta x}[/tex]

[tex]k=\frac{39,2}{0,05}[/tex]

[tex]k=784 N/m[/tex]

Usando la misma ecuación y sabiendo k tenemos:

[tex]\Delta x=\frac{F}{k}[/tex]

[tex]\Delta x=\frac{68,6}{784}[/tex]

[tex]\Delta x=8,8 cm[/tex]

Espero esto te ayude!

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