LacrosseGator6322 LacrosseGator6322
  • 23-07-2020
  • Mathematics
contestada

If F(x) = f(g(x)), where f(−4) = 8, f '(−4) = 3, f '(−3) = 5, g(−3) = −4, and g'(−3) = 6, find F '(−3). F '(−3)

Respuesta :

pedrocarratore
pedrocarratore pedrocarratore
  • 23-07-2020

Answer:

F'(-3) = 18

Step-by-step explanation:

Let g(x) = u and apply the chain rule

[tex]F(x)=f(g(x))=f(u)\\F'(x)=\frac{df(u)}{du}[/tex]

[tex]\frac{du}{dx}=g'(x)[/tex]

[tex]\frac{df(u)}{du}*\frac{du}{dx} = \frac{df(u)}{dx}\\F'(x)= \frac{df(u)}{du}*g'(x)\\F'(x)= f'(u)*g'(x)\\F'(x)= f'(g(x))*g'(x)[/tex]

We now have all of the necessary definite values to solve the expression for x= -3:

[tex]F'(-3)= f'(g(-3))*g'(-3)\\F'(-3)= f'(-4)*6\\F'(-3)= 3*6\\F'(-3)= 18[/tex]

Finally, we have that F'(-3)= 18.

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