Answer:
[tex]j=4\\k=10[/tex]
Step-by-step explanation:
[tex]8x^3 - 125[/tex]
[tex]\left(2x\right)^3-5^3[/tex]
Use this formula:
[tex]x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)[/tex]
Where,
[tex]x=2x\\y=5[/tex]
Substitute in the values.
[tex]\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)[/tex]
[tex]\left(2x-5\right)\left(4x^2+10x+25\right)[/tex]
