Answer:
Centripetal acceleration of the wheel is [tex]0.145\ m/s^2[/tex].
Explanation:
We have,
Diameter of a Ferris wheel is 60 m
Radius of the wheel is 30 m
Speed of the wheel is 2.09 m/s
It is required to find the centripetal  acceleration of the wheel. The formula of centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2.09)^2}{30}\\\\a=0.145\ m/s^2[/tex]
So, the centripetal acceleration of the wheel is [tex]0.145\ m/s^2[/tex].
