Respuesta :

Cathenna

Answer:

[tex] \boxed{D. 20 {x}^{6} {y}^{4}} [/tex]

Step-by-step explanation:

[tex](5 {x}^{2} y)(4 {x}^{4} {y}^{3} ) = 20 {x}^{6} {y}^{4} [/tex]

Rule need to remember to solve such questions:

[tex] {a}^{x} \times {a}^{y} = {a}^{x + y} [/tex]

Answer:

No its the fourth option

Step-by-step explanation:

Add common expressions