lhanshaw lhanshaw

24-08-2016
Mathematics

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lim as x approaches 5 from the right (x-5)/(x^2-25)

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nobillionaireNobley nobillionaireNobley

24-08-2016

[tex] \lim_{x \to 5^+} \frac{x-5}{x^2-25} = \lim_{x \to 5^+} \frac{x-5}{(x-5)(x+5)} = \lim_{x \to 5^+} \frac{1}{x+5} = \infty[/tex]

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