qui7noyD6Banabribeck
qui7noyD6Banabribeck qui7noyD6Banabribeck
  • 24-07-2016
  • Physics
contestada

What is the nuclear binding energy in joules for an atom of helium–4? Assume the following: Mass defect = 5.0531 × 10-29 kilograms. Use E = mc2, with c = 3 × 108 m/s.

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meerkat18
meerkat18 meerkat18
  • 01-08-2016
The equation given, E = mc², can be directly used to determine the unknown amount of nuclear binding energy. Substitute the values given to the equation,
               E = (5.0531 x 10^-29 kg) x (3 x 10^8 m/s)² = 4.548 x 10^-12 J
Thus, the nuclear binding energy is equal to 4.548 x 10^-12 J. 
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zamariastephens zamariastephens
  • 15-06-2018
the correct answer is 4.53 * 10-12 joules
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