Answer:
11.6 grams of MgO can be produced with 4.63 grams of oxygen.
Explanation:
[tex]2Mg+O_2\rightarrow 2MgO[/tex]
Mass of oxygen gas = 4.63 g
Moles of oxygen gas = [tex]\frac{4.63 g}{32 g/mol}=0.145 mol[/tex]
According to reaction, 1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:
[tex]\frac{2}{1}\times 0.145 mol=0.29 mol[/tex] of magnesium oxide
Mass of 0.2894 moles of magnesium oxide:
= 0.29 mol × 40 g/mol = 11.6 g
11.6 grams of MgO can be produced with 4.63 grams of oxygen.
