Answer:
L = 1.26 μH
Explanation:
Length of the solenoid, l = 3.0 cm = 0.03 m
Cross sectional area of the solenoid, A = 0.50 cm² = 0.5 * 10⁻⁴ m²
A = 5 * 10⁻⁵ m²
N = 300 turns
The inductance of a coil is given by [tex]L = \frac{2 \mu NA}{l}[/tex]...................(1)
Magnetic constant, [tex]\mu = 4\pi * 10^{-7} H/m[/tex]
Substituting the appropriate values into equation (1)
[tex]L = \frac{2 *(4\pi*10^{-7}) * 300* 5 * 10^{-5} }{0.03}\\L = 0.00000126 H\\L = 1.26 * 10^{-6} H\\ L = 1.26 microHenry[/tex]
