kellerpaula kellerpaula
  • 22-03-2020
  • Mathematics
contestada

Solving Exponential Equations (lacking a common base)

(0.52)^q=4

Respuesta :

lordsonmyk
lordsonmyk lordsonmyk
  • 22-03-2020

Answer:

q = log4 / log0.53

q = -2.189

Step-by-step explanation:

(0.53)^q = 4

Taking log of both sides!

q log 0.53 = log 4

q = log 4 / log 0.53

q = 0.602 / -0.275

q = - 2.189

This can be checked to confirm correctness.

Substituting q = -2.189

(0.53)^ -2.189 = 1/ 0.249

= 4.01 Proved!

(Note that the "1" is because of the negative sign)

Answer Link
amna04352
amna04352 amna04352
  • 22-03-2020

Answer:

q = -2.12

Step-by-step explanation:

lg both sides

lg(0.52^q) = lg4

qlg0.52 = lg4

q = lg4/lg0.52

q = -2.12

Answer Link

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