mireyagonzaless8677 mireyagonzaless8677
  • 26-02-2020
  • Physics
contestada

A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?

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MechEngineer
MechEngineer MechEngineer
  • 27-02-2020

Answer:

447 K

Explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

[tex]T_2 = T_1\frac{P_2}{P_1}\frac{V_2}{V_1}[/tex]

Since pressure is tripled, then [tex]P_2 / P_1 = 3[/tex]. Volume is halved, then [tex]V_2 / V_1 = 0.5[/tex]

[tex]T_2 = 298*3*0.5 = 447 K[/tex]

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nwandukelechi nwandukelechi
  • 27-02-2020

Explanation:

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