[tex]f(g(x)) = 2\sqrt{2x-1}[/tex]
Solution:
Given that,
[tex]f(x) = \sqrt{x+9}\\\\g(x) = 8x - 13[/tex]
We have to find f(g(x))
Which means, substitute g(x) value in place of x in f(x)
Therefore,
[tex]f(g(x)) = \sqrt{8x - 13 + 9}\\\\Simplify\\\\f(g(x)) = \sqrt{8x -4}\\\\Take\ common\ factor\ out\\\\f(g(x)) = \sqrt{4(2x-1)}\\\\f(g(x)) = 2\sqrt{2x-1}[/tex]
Thus f(g(x)) is found
