Diavionreineking Diavionreineking

22-06-2016
Chemistry

contestada

Given that the molar mass of NaNO3 is 85.00 g/mol, what mass of NaNO3 is needed to make 4.50 L of a 1.50 M NaNO3 solution?

Respuesta :

Willchemistry Willchemistry

24-06-2016

mass = molarity x molar mass( NaNO₃) x volume

mass = 1.50 x 85.00 x 4.50

mass = 573.75 g of NaNO₃

hope this helps!

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rsheftal rsheftal

03-02-2021

Answer:

B. 574g

Explanation:

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