Answer:
Step-by-step explanation:
(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]
= [2a + 3b - 16c]×[2a + 3b + 16c]
Answer:
Step-by-step explanation:
hello :
(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]
= [2a + 3b - 16c]×[2a + 3b + 16c]
by identity : x²- y² = (x-y)(x+y) when x= 2a+3b and y = 16c
