Answer:
ΔEAB ≅ΔFCD
Step-by-step explanation:
As ABCD is a parallelogram opposite sides are equal s AE ≅CF ,also AB≅ DC . Both E and F bisect the opposite lines in equal halves.
The parallelogram has a property that its opposite angles are equal . Therefore ∠c≅∠a, ∠d≅∠b
Using the SAA≅SAA postulate we conclude that ΔEAB ≅ΔFCD
