Answer:
The distance between home to second base is 92.412 feet
Explanation:
IF we draw a diagram, it is in the shape of a right angled triangle
Where, the distance from home to 2nd base is the hypotenuse
With legs = 65 ft
Applying Pythagoras theorem,
[tex]\mathrm{H}^{2}=\mathrm{B}^{2}+\mathrm{P}^{2}[/tex]
[tex]H^2[/tex] = (65*65) + (65*65)
[tex]H^2[/tex] = 8540
H = 92.412 FEET
Therefore, the distance between home to second base is 92.412 feet
