Answer:
[tex]y=(x+3)^2-1\\y=x^2+6x+8[/tex]
Step-by-step explanation:
Given:
Vertex of the parabola is, [tex](h,k)=(-3,-1)[/tex]
Equation of the parabola in vertex form is given as:
[tex]y=(x-h)^2+k[/tex]
Plug in [tex]h=-3,k=-1[/tex]. This gives,
[tex]y=(x-(-3))^2+(-1)\\y=(x+3)^2-1[/tex]
Therefore, the equation of the given graph is
[tex]y=(x+3)^2-1\\y=x^2+6x+8[/tex].
