Answer:
40th term of arithmetic sequence = 442
Step-by-step explanation:
Here arithmetic sequence is given as 13, 24, 35, ....
First term, f = 13
Common difference , d = 24 - 13 = 11
We know that n th term of AP is
[tex]t_n=f+(n-1)d[/tex]
We need to find 40 th term, that is n = 40
Substituting
[tex]t_{40}=13+(40-1)\times 11=13+39\times 11=13+429=442[/tex]
40th term of arithmetic sequence = 442
