md2001 md2001
  • 26-05-2016
  • Mathematics
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how do you substitute x+7y=0 into 2x-8y=22

how do you substitute x7y0 into 2x8y22 class=

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SmarticalParticals
SmarticalParticals SmarticalParticals
  • 26-05-2016
First solve for x in the first equation

x + 7y = 0
x = -7y

since x = -7y we can substitute -7y into the other equation wherever there is an x

2x - 8y = 22
2(-7y) - 8y = 22
-14y - 8y = 22
-22y = 22
y = -1

Now let's substitute -1 back into either of the original equations so we can solve for x

x + 7y = 0
x + 7(-1) = 0
x - 7 = 0
x = 7

So your solution set is

(7, -1)
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