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The diagram below represents a horizontal force of 20 newtons applied to a 5.0 kilogram box to push it and
rough, horizontal floor at a constant velocity of 3.0 m/s to the right.
3.0 m/s
20 N
5.0 kg
B. Determine the magnitude of the force of friction acting on the box. Explain your answer.

Respuesta :

skyluke89

Answer:

20 N

Explanation:

There are two forces acting on the box:

- The force of push, F, forward, of magnitude F = 20 N

- The force of friction, [tex]F_f[/tex], backward

So, the equation of motion for the box is

[tex]F-F_f = ma[/tex]

where

m = 5.0 kg is the mass of the box

a is its acceleration

The box is sliding at constant velocity: this means that its acceleration is zero

a = 0

So, the equation becomes

[tex]F-F_f = 0[/tex]

Therefore, we can find the magnitude of the force of friction:

[tex]F_f = F =  20 N[/tex]

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