Travon9791 Travon9791
  • 21-10-2019
  • Mathematics
contestada

Solve the following systems of equations r=2(s-t) ; 2t=3(s-r) ; r+t=2s-3.

Respuesta :

valetta valetta
  • 22-10-2019

Answer:

r = 2

s = 4

t = 3

Step-by-step explanation:

Given:

r = 2(s - t)  

or

r = 2s - 2t          .............(1)

2t = 3( s - r)       ...............(2)

r + t = 2s - 3         .............(3)

substituting 1 in 3, we get

2(s - t) + t = 2s - 3

or

2s - 2t + t = 2s - 3

or

-t = 2s - 3 - 2s

or

t = 3

substituting t in 3 we get

r + 3 = 2s - 3

or

r = 2s - 6

substituting r and t in 2, we get

2 × 3 = 3( s - (2s - 6))

or

2 = s - 2s - 6

or

- 4 = -s

or

s = 4

substituting value of s and t in 1 , we get

r = 2 ( 4 - 3 )

or

r = 2

thus,

r = 2

s = 4

t = 3

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