Blairm5193 Blairm5193
  • 21-10-2019
  • Mathematics
contestada

Find cos(405°) and sin(405°). Identify the measure of the reference angle.

Respuesta :

aristeus aristeus
  • 24-10-2019

Answer:

Reference angle will be [tex]45^{\circ}[/tex]

[tex]cos(45^{\circ})=0.707[/tex]

[tex]sin(45^{\circ})=0.707[/tex]

Step-by-step explanation:

We have given [tex]cos(405^{\circ})[/tex]

Which can be written as [tex]cos(405^{\circ})=cos(360+45)[/tex]

We know that [tex]45^{\circ}[/tex] is present in first quadrant

And in first quadrant the reference angle is angle itself

So reference angle will be = 45°

Now [tex]cos(405)=cos(2\pi +45)=cos45^{\circ}=0.707[/tex]

And [tex]sin(405)=sin(2\pi +45)=sin45^{\circ}=0.707[/tex]

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