Answer: [tex]1027nm[/tex]
Explanation:
Using Weins displacement law:
[tex]\lambda_{max}=\frac{b}{T}[/tex]
where [tex]\lambda_{max}[/tex] = wavelength
b = constant =[tex]2898\micro mK[/tex]
T = Temperature in Kelvin = 2822 K
Putting the values we get:
[tex]\lambda _{max}=\frac{2898\micro mK}{2822K}=1.027\micro m[/tex]
[tex]1\micro m=10^3nm[/tex]
[tex]1.027\micro m=\frac{10^3}{1}\times 1.027=1.027\times 10^3nm[/tex]
Thus wavelength of the spectral maximum in the emission of light by this star is [tex]1027nm[/tex]
