Answer:
W = 3.73 eV
Explanation:
Given data:
wavelength of photons 240 nm
kinetic energy 1.45 eV
B y using photoelectric equation
Kinetic Energy  =  Photon Energy - work friction
[tex]K.E = \frac{hc}{\lambda} -W[/tex]
[tex]\frac{hc}{\lambda} = \frac{6.63\times 10^{-34}\times 3\times 10^8}{240\times 10^{-9}\times 1.6\times 10^{-19}} eV[/tex]
               = 5.179 eV
               = 5.18 eV[tex]
W = Â \frac{hc}{\lambda} - K.E[/tex]
   = (5.18 - 1.45) eV
W = 3.73 eV
