Answer:
[tex]\large\boxed{y=\dfrac{2}{3}}[/tex]
Step-by-step explanation:
[tex]2y+4y=6-3y\\\\6y=6-3y\qquad\text{add}\ 3y\ \text{to both sides}\\\\6y+3y=6-3y+3y\\\\9y=6\qquad\text{divide both sides by 9}\\\\\dfrac{9y}{9}=\dfrac{6}{9}\\\\y=\dfrac{6:3}{9:3}\\\\y=\dfrac{2}{3}[/tex]
