Answer:
The correct answer is 0.1
Step-by-step explanation:
We know the total no of ways in which 3 boys and 3 girls can be seated equals 6!
Now since we want all the 3 girls and the 3 boys to sit together
Let B1 , B2 , B3 be the boys and G1, G2, G3 be the boys and girls respectively
the no of ways to arrange boys = 3!
Similarly the number of ways to arrange girls = 3!
Thus the total no of ways to arrange both boys and girls = 3! x 3!
Thus the probability is given by
[tex]P(E)=\frac{2\times 3!\times 3!}{6!}=\frac{1}{10}=0.1[/tex]
